A) \[\Delta {{G}^{o}}=-2.30\,RT\,\log \,K\]
B) \[\Delta {{G}^{o}}=-2.30\,RT\,\log \,K\]
C) \[\Delta G=-2.30\,RT\,\log \,K\]
D) \[\Delta G=2.30\,RT\,\log \,K\]
Correct Answer: A
Solution :
\[\Delta {{G}^{o}}=-2.30RT\,\log \,K\]because at equilibrium \[\Delta G=0\]
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