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NEET Sample Paper NEET Sample Test Paper-39

  • question_answer
    A conveyor belt is moving at a constant speed of 2 m/s. A box is gently dropped on it. The co- efficient of friction between them is\[\mu =0.5.\]The distance that the box will move relative to belt before coming to rest on it taking \[g=10\,m{{s}^{-2}}\]is:

    A)  1.2 m         

    B)  0.6 m

    C)  zero          

    D)  0.4 m

    Correct Answer: D

    Solution :

     Force, \[F=\mu mg\] Retardation of the block on the belt \[a=\frac{F}{m}=\frac{\mu mg}{m}=\mu g\] From, \[{{v}^{2}}={{u}^{2}}+2as\] \[0={{(2)}^{2}}-2(\mu g)s\] \[s=\frac{4}{2\times 0.5\times 10}=0.4\,m\]


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