A) \[\Delta S\]is negative and therefore\[\Delta H\]should be highly positive.
B) \[\Delta S\] is negative and therefore,\[\Delta H\]should be highly negative.
C) \[\Delta S\]is positive and therefore\[\Delta H\]should be negative.
D) \[\Delta S\]is positive and therefore \[\Delta H\]should also be highly positive.
Correct Answer: B
Solution :
For adsorption \[\Delta S<0\]and for a spontaneous change\[\Delta G=-ve\] Hence\[\Delta \Eta \]should be highly negative which is clear from the equation \[\Delta G=\Delta H-T\Delta S\] \[=-\Delta \Eta -\Tau (-\Delta S)=-\Delta H+T\Delta S\] So if \[\Delta \Eta \]is highly negative, \[\Delta G\]will also be -ve,
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