NEET Sample Paper NEET Sample Test Paper-39

  • question_answer
    The pressure exerted by 6.0 g of methane gas ma \[0.03\,{{m}^{3}}\]vessel at \[129{}^\circ C\] is: (Atomic masses of C \[=12.01,\,H=1.01\]and\[R=8.314\,J{{K}^{-1}}mo{{l}^{-1}}\]

    A)  215216 Pa   

    B)  13409 Pa

    C)  41648 Pa

    D)  31684 Pa

    Correct Answer: C

    Solution :

     \[PV=\frac{w}{M}RT\] \[P\times \,\,0.03=\frac{6}{16.05}\times 8.314\times 402\] \[\therefore \]\[P=41647.7\,Pa\]


You need to login to perform this action.
You will be redirected in 3 sec spinner