A) \[6.67\,km\,{{s}^{-1}}\]
B) \[7.76\,km\,{{s}^{-1}}\]
C) \[8.56\,km\,{{s}^{-1}}\]
D) \[9.13\,km\,{{s}^{-1}}\]
Correct Answer: B
Solution :
For the satellite revolving around earth \[{{v}_{0}}=\sqrt{\frac{G{{M}_{e}}}{({{R}_{e}}th)}}=\sqrt{\frac{G{{M}_{e}}}{{{R}_{e}}\left( 1+\frac{h}{{{R}_{e}}} \right)}}=\sqrt{\frac{g{{R}_{e}}}{1+\frac{h}{{{R}_{e}}}}}\] Substituting the values \[{{v}_{0}}=\sqrt{60\times {{10}^{6}}}\,m/s\] \[{{v}_{0}}=7.76\times {{10}^{3}}\,m/s=7.76\,km/s\]
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