NEET Sample Paper NEET Sample Test Paper-39

  • question_answer A remote-sensing satellite of earth revolves in a circular orbit at a height of \[0.25\times {{10}^{6}}\,m\]above the surface of earth. If earth's radius is \[6.38\times {{10}^{6}}\,m\]and \[g=9.8\,m{{s}^{-2}},\]then the orbital speed of the satellite is

    A) \[6.67\,km\,{{s}^{-1}}\]

    B) \[7.76\,km\,{{s}^{-1}}\]

    C) \[8.56\,km\,{{s}^{-1}}\]

    D) \[9.13\,km\,{{s}^{-1}}\]  

    Correct Answer: B

    Solution :

      For the satellite revolving around earth \[{{v}_{0}}=\sqrt{\frac{G{{M}_{e}}}{({{R}_{e}}th)}}=\sqrt{\frac{G{{M}_{e}}}{{{R}_{e}}\left( 1+\frac{h}{{{R}_{e}}} \right)}}=\sqrt{\frac{g{{R}_{e}}}{1+\frac{h}{{{R}_{e}}}}}\] Substituting the values \[{{v}_{0}}=\sqrt{60\times {{10}^{6}}}\,m/s\] \[{{v}_{0}}=7.76\times {{10}^{3}}\,m/s=7.76\,km/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner