• # question_answer A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet each towards earth, their respective kinetic energies will be in the ratio of A)  $\sqrt{2}:1$B)  2 : 1C)  1 : 2D) $1:\sqrt{2}$

Kinetic energy $=\frac{1}{2}m{{v}^{2}}$ As both balls are falling through the same height, therefore they possess same velocity. but $KE\propto m$ (If$v=$constant) $\therefore$ $\frac{{{(KE)}_{1}}}{{{(KE)}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{2}{4}=\frac{1}{2}$