A) \[{{s}_{2}}=2{{s}_{1}}\]
B) \[{{s}_{2}}=3{{s}_{1}}\]
C) \[{{s}_{2}}=4{{s}_{1}}\]
D) \[{{s}_{2}}={{s}_{1}}\]
Correct Answer: C
Solution :
If the particle is moving in a straight line under the action of a constant force or under constant acceleration [a] Using, \[s=ut+\frac{1}{2}a{{t}^{2}}.\] Since the body starts from the rest\[u=0\] \[\therefore \] \[s=\frac{1}{2}a{{t}^{2}}\] Now, \[{{s}_{1}}=\frac{1}{2}a{{(10)}^{2}}\] ?(i) and \[{{s}_{2}}=\frac{1}{2}a{{(20)}^{2}}\] ?(ii) Dividing Eq. (i) and Eq. (ii), we get \[\frac{{{s}_{1}}}{{{s}_{2}}}=\frac{{{(10)}^{2}}}{{{(20)}^{2}}}\Rightarrow {{s}_{2}}=4{{s}_{1}}\]
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