A) \[{{C}_{6}}{{H}_{5}}CH({{C}_{6}}H)Br\]
B) \[{{C}_{6}}{{H}_{5}}CH(C{{H}_{3}})Br\]
C) \[{{C}_{6}}{{H}_{5}}C(C{{H}_{3}})({{C}_{6}}{{H}_{5}})Br\]
D) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}Br\]
Correct Answer: C
Solution :
\[{{S}_{N}}1\]reaction involves the formation of carbocations, hence higher the stability of carbocation, more will be the reactivity of the parent alkyl halide. Thus tertiary carbocation formed from is stabilized by two phenyl groups and one methyl group, hence most stable.\[{{C}_{6}}{{H}_{5}}-\underset{{{C}_{6}}{{H}_{5}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-Br\xrightarrow{{}}{{C}_{6}}{{H}_{5}}-\underset{C{{H}_{3}}}{\mathop{\underset{\uparrow }{\mathop{\underset{|}{\overset{+}{\mathop{C}}}\,}}\,}}\,-{{C}_{6}}{{H}_{5}}\]
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