A) \[SO_{3}^{2-}\]
B) \[SO_{4}^{2-}\]
C) \[{{S}_{4}}O_{6}^{2-}\](Tetrathionate)
D) \[{{S}_{2}}O_{6}^{2-}\]
Correct Answer: C
Solution :
\[2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\to 2Nal+N{{a}_{2}}{{S}_{4}}{{O}_{6}}\]
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