question_answer

When\[C{{l}_{2}}\]gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

A)  Zero to -1 and zero to +3

B)  Zero to +1 and zero to -3

C)  Zero to +1 and zero to -5

D)  Zero to-land zero to+5

Correct Answer: D

Solution :

 In disproportionation reaction, the same element undergoes oxidation as well as reduction. In this process, oxidation number of chlorine changes from 0 to -1 and 0 to +5.