A) \[6.023\times {{10}^{-23}}\,c{{m}^{3}}\]
B) \[3.0\times {{10}^{-23}}\,c{{m}^{3}}\]
C) \[5.5\times {{10}^{-23}}\,c{{m}^{3}}\]
D) \[9.0\times {{10}^{-23}}\,c{{m}^{3}}\]
Correct Answer: B
Solution :
\[1000\,g\,{{H}_{2}}O=1000\,c{{m}^{3}}{{H}_{2}}O\] \[\frac{1000}{18}\,mole\,{{H}_{2}}O=1000\,c{{m}^{3}}\,{{H}_{2}}O\] \[\frac{1000}{18}\times 6.023\times {{10}^{23}}\]Molecule of \[{{H}_{2}}O\] \[=1000\,c{{m}^{3}}{{H}_{2}}O\] \[\Rightarrow \]Volume of molecule \[=\frac{1000}{1000}\times \frac{18}{6.023\times {{10}^{23}}}\] \[=3.0\times {{10}^{-23}}c{{m}^{3}}.\]
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