A) \[4{{E}_{n}}\]
B) \[{{E}_{n}}/4\]
C) \[2{{E}_{n}}\]
D) \[{{E}_{n}}/2\]
Correct Answer: A
Solution :
We have \[{{E}_{n}}=\frac{-2{{\pi }^{2}}m{{K}^{2}}{{Z}^{2}}{{e}^{4}}}{{{n}^{2}}{{h}^{2}}}.\]For helium Z = 2 hence requisite answer is \[4{{E}_{n}}\] [c] \[{{r}_{n}}\propto {{n}^{2}}\]
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