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NEET Sample Paper NEET Sample Test Paper-37

  • question_answer
    Change in enthalpy for reaction \[2{{H}_{2}}{{O}_{2}}(l)\xrightarrow{{}}2{{H}_{2}}O(l)+{{O}_{2}}(g)\] if heat of formation of \[{{H}_{2}}{{O}_{2}}(l)\]and \[{{H}_{2}}O(l)\] are -188 and -286 kJ/mol respectively is

    A)  -196 kJ/mol 

    B)  +196 kJ/mol

    C)  +948 kJ/mol 

    D)  -948 kJ/mol

    Correct Answer: A

    Solution :

    \[2{{H}_{2}}{{O}_{2}}(\ell )\xrightarrow{{}}2{{H}_{2}}O(\ell )+{{O}_{2}}(g)\]   \[\Delta \Eta =?\] \[\Delta \Eta =[(2\times \Delta {{\Eta }_{f}}\,of\,{{H}_{2}}O(l)+(\Delta {{\Eta }_{f}}\,of\,{{O}_{2}})]\] \[-[(2\times \Delta {{\Eta }_{f}}of\,{{H}_{2}}{{O}_{2}}(l))]\] \[=[(2\times -286)+(0)-(2\times -188)]\] \[=[-572+376]=-196\,kJ/mol\]


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