A) 15 L of \[{{H}_{2}}\]gas at STP
B) 5 L of \[{{N}_{2}}\]gas at STP
C) 0.5 g of \[{{H}_{2}}\]gas
D) 10 g of \[{{O}_{2}}\]gas
Correct Answer: A
Solution :
Moles of \[{{H}_{2}}=\frac{15}{22.4}=0.67\] Moles of \[{{N}_{2}}=\frac{5}{22.4}=0.22\] Moles of \[{{H}_{2}}=\frac{0.5}{2}=0.25\] Moles of \[{{O}_{2}}=\frac{10}{32}=0.31\] Larger is the number of mole, more is the number of molecule.
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