A) \[2\,\Omega \]
B) \[4\,\Omega \]
C) \[8\,\Omega \]
D) \[16\,\Omega \]
Correct Answer: B
Solution :
Given circuit is a balanced Wheatstone's bridge circuit, hence it can be redrawn as follows.
\[{{R}_{AB}}=\frac{12\times 6}{(12+6)}=4\,\Omega .\]
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