question_answer

On the basis of the information available from the reaction \[\frac{4}{3}Al+{{O}_{2}}\xrightarrow{{}}\frac{2}{3}A{{l}_{2}}{{O}_{3}},\Delta G=\]\[-827\,kJ\,mo{{l}^{-1}}\]of \[{{O}_{2}},\] the minimum emf required to carry out an electrolysis of\[A{{l}_{2}}{{O}_{3}}\]is\[(F=96500\,C\,mo{{l}^{-1}})\] 

A)  8.56 V       

B)  2.14 V

C)  4.28 V       

D)  6.42 V