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NEET Sample Paper NEET Sample Test Paper-36

  • question_answer
    1.0 g of a non-electrolyte solute (molar mass\[250\,g\,mo{{l}^{-1}}\]) was dissolved in 51.2 g of benzene. If the freezing point depression constant of benzene is \[5.12\,K\,kg\,mo{{l}^{-1}},\]the lowering in freezing point will be

    A)  0.5 K         

    B)  0.4 K

    C)  0.2 K         

    D)  0.3 K                

    Correct Answer: B

    Solution :

     \[\Delta \Tau =\frac{1000\times {{K}_{f}}\times w}{m\times W}\] \[=\frac{1000\times 5.12\times 1}{250\times 51.2}=0.4\,K\]


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