A) C-14 fraction is the same in all the objects
B) C-14 is highly insoluble
C) ratio of C-14 and C-12 is constant in living species
D) all of the above
Correct Answer: C
Solution :
By carbon dating method. Age of wood\[=\frac{2.303}{0.693}\times {{t}_{1/2}}\log \left( \frac{{{N}_{0}}}{N} \right)\] \[\frac{\text{ratio}\,\text{of}\,{{\text{C}}^{\text{14}}}\text{/}{{\text{C}}^{\text{12}}}\,\text{in}\,\text{living}\,\text{wood}}{\text{ratio}\,\text{of}\,{{\text{C}}^{\text{14}}}\text{/}{{\text{C}}^{\text{12}}}\,\text{in}\,\text{dead}\,\text{wood}}\] Hence it is based upon the ratio of \[{{\text{C}}^{\text{14}}}\] and \[{{\text{C}}^{\text{12}}}\].
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