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NEET Sample Paper NEET Sample Test Paper-36

  • question_answer
    When 1 mole of gas is heated at constant volume. Temperature is raised from 298 to 308 K. Heat supplied to the gas is 500 J. Then which statement is correct?

    A) \[q=-W=500\,J,\Delta U=0\]

    B) \[q=\Delta U=500\,J,W=0\]

    C) \[q=W=500\,J,\,\Delta U=0\]   

    D) \[\Delta U=0,q=W=-500\,J\]

    Correct Answer: B

    Solution :

     We know that, \[\Delta \Eta =\Delta E+P\Delta V\] When, \[\Delta V=0,\,\therefore \,\Delta H=\Delta E\] From the first law of thermodynamics, \[\Delta \Epsilon =q-W\] In the given problem, \[\Delta h=500\,j\] \[-W=-P\Delta V,\Delta V=0\] So, \[\Delta \Epsilon =q=500\,J\]


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