A) 310 nm
B) 620 nm
C) 1200 nm
D) 2100 nm
Correct Answer: B
Solution :
\[\lambda =\frac{12375}{{{W}_{0}}}=\frac{12375}{2}=6187.5\overset{\text{o}}{\mathop{\text{A}}}\,=620\,nm\]
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