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NEET Sample Paper NEET Sample Test Paper-35

  • question_answer
    In alkaline condition \[KMn{{O}_{4}}\] reacts as \[2KMn{{O}_{4}}+2KOH\xrightarrow{{}}2{{K}_{2}}Mn{{O}_{4}}+{{H}_{2}}O+O\]         The equivalent weight  of \[KMn{{O}_{4}}\] would be

    A)  \[158.0~\]

    B)  \[79.0\]

    C)  \[52.7\]              

    D)  \[31.6\]

    Correct Answer: A

    Solution :

    Molecular weight of \[Mn{{O}_{4}}=39+55+64=158\] \[2K\overset{+7}{\mathop{M}}\,n{{O}_{4}}\xrightarrow{O{{H}^{-}}}2{{K}_{2}}\overset{+6}{\mathop{M}}\,n{{O}_{4}}\] Here one electron gain. Hence the equivalent weight of \[KMn{{O}_{4}}\]is equal to its molecular weight i.e. 158


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