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NEET Sample Paper NEET Sample Test Paper-35

  • question_answer
    Dissolving \[120\text{ }g\]of urea (mol. wt. 60) in \[1000\text{ }g\]of water gave a solution of density\[1.15\text{ }g/ml\]. The molarity of the solution is

    A)  \[1.78\text{ }M\]

    B)  \[2.00\text{ }M\]

    C) \[2.05\text{ }M\]            

    D)  \[2.22M\]

    Correct Answer: C

    Solution :

    Molarity \[=\frac{Moles\,of\,solute}{Volume\,of\,solution\,in\,litre}\] Number of moles of urea \[=\frac{120}{60}=2\] Weight of solution = weight of solute + weight of solvent \[=120\text{ +}1000=1120\text{ }g\] Volume\[=\frac{1120}{1.15g/ml}\times \frac{1}{1000ml/L}=0.974L\] Molarity \[=\frac{2}{0.974}=2.05\,M\]


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