A) \[2.3\,eV~\]
B) \[0.025\,eV\]
C) \[23\,eV\]
D) \[0.23\,eV\]
Correct Answer: A
Solution :
Energy is given by, \[E=\frac{hc}{\lambda }\,J=\frac{hc}{\lambda \times 1.6\times {{10}^{-19}}}eV\] Here, \[\lambda =5400\overset{\text{o}}{\mathop{\text{A}}}\,=5400\times {{10}^{-10}}m\] \[\Rightarrow \] \[E=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{5400\times {{10}^{-10}}1.6\times {{10}^{-19}}}eV\] \[\Rightarrow \] \[E=2.3eV.\]
You need to login to perform this action.
You will be redirected in
3 sec
