A) \[5I,-3I\]
B) \[9I,I\]
C) \[9I,-I\]
D) \[5I,3I\]
Correct Answer: B
Solution :
In interference intensity obtained is given by \[{{I}_{0}}={{I}_{1}}+{{I}_{2}}+2\sqrt{{{I}_{1}}{{I}_{2}}\cos \theta }\] If \[\cos \theta =1,\] (maximum value) \[{{I}_{0}}\] is minimum Here, \[{{I}_{1}}=4I,\] \[{{I}_{2}}=I\] \[\therefore \] \[{{I}_{\max }}=4I+I+2\sqrt{4I\times I}=qI\] \[{{I}_{\min }}=4I+I-2\sqrt{4I\times I}=I\]
You need to login to perform this action.
You will be redirected in
3 sec
