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NEET Sample Paper NEET Sample Test Paper-35

  • question_answer
    Separation between slits is halved and between screen and slits is doubled. Find fringe width if original is \[\omega \]:

    A)  \[\omega \]                  

    B)  \[9\,\omega \]

    C)  \[4\,\omega \]                

    D)  \[2\,\omega \]

    Correct Answer: C

    Solution :

    In Young's double slit experiment interference width is given by fringe width \[(w)=\frac{\lambda D}{d}\] Where, d = sepration between the slits D = sepration between screen and slits Let     \[w=\frac{\lambda D}{d}\]      (Given)        .....(i) In another case, d is taken as d/2 and D as 2D. \[\therefore \] \[w=\frac{\lambda \times (2D)}{\left( \frac{d}{2} \right)}=4\times \frac{\lambda D}{d}=4\omega \]


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