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NEET Sample Paper NEET Sample Test Paper-35

  • question_answer
    Distance between successive compression and rare fraction is 1m and velocity of sound is \[360\text{ }m{{s}^{-1}}\] find frequency:

    A) \[180\,Hz\]          

    B)  \[45\,Hz\]

    C)  \[120\,Hz\]          

    D)  \[90\,Hz\]

    Correct Answer: A

    Solution :

    From formula \[U=n\lambda \] Here,       \[\lambda =2d=2m,\,\,V=360m{{s}^{-1}}\] Because distance between successive compression and refraction is one half of the wavelength. \[h=\frac{V}{\lambda }=\frac{360}{2}=180\,Hz.\]


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