question_answer

The number of atoms in \[100\,g\]of a FCC crystal with density \[d=10\text{ }g/c{{m}^{3}}\]and cell edge as 200 pm is equal to:-                                            

A)  \[3\times {{10}^{25}}\]           

B) \[5\times {{10}^{24}}\]              

C)  \[1\times {{10}^{25}}\]            

D)  \[2\times {{10}^{25}}\]