question_answer

1 mol of anhydrous \[MgC{{l}_{2\,(s)}}\] dissolve in water and e liberate 25cal. Heat of hydration of \[MgC{{l}_{2}}\](s) is \[-30\]Cal. Then calculate heat of solution of \[MgC{{l}_{2}}\]. \[2{{H}_{2}}O\](s) :-

A)  \[55\text{ }cal/mol\]        

B)  \[~+5\text{ }cal/mol\]

C)  \[-5\text{ }cal/mol\]        

D)  \[-55\text{ }cal/mol\]