NEET Sample Paper NEET Sample Test Paper-34

  • question_answer
    If the percentage error in the measurement of radius of a sphere is 2%, then the maximum percentage errors in the measurements of its diameter, surface area and volume are respectively

    A)  2%, 4% and 4 %

    B)  6%, 4% and 2%

    C)  6%, 6% and 6%

    D)  2%, 4% and 6%

    Correct Answer: D

    Solution :

    \[\because \]  \[D=2R\]\[\therefore \] \[\frac{\Delta D}{D}\times 100=\frac{\Delta R}{R}\times 100=2%\] \[\because \]\[A=4\pi {{R}^{2}}\]\[\therefore \]\[\frac{\Delta A}{A}\times 100=2\frac{\Delta R}{R}\times 100=4%\] \[\because \]\[V=\frac{4}{3}\pi {{R}^{3}}\]\[\therefore \]\[\frac{\Delta V}{V}\times 100=3\frac{\Delta R}{R}\times 100=6%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner