• # question_answer A particle is executing SHM according to the equation $x=A\,\sin (\omega t+\phi ).$. At any time t, it is found that the total phase of the particle is $\frac{7\pi }{6}$ then the particle is at :-                          A)  $x=A/2$and moving in $+\text{ }x$direction             B)  $x=-A/2$and moving in $-\text{ }x$directionC)  $x=A/2$and moving in $-\text{ }x$ directionD)  $x=-A/2$and moving in $-\text{ }x$direction

Phase angle $\frac{7\pi }{6}=\pi +\frac{\pi }{6}$ Particle is moving towards $-x$direction Instantaneous displacement $x=A\,\sin \frac{7\pi }{6}=-\frac{A}{2}$