A) \[{{[PtC{{l}_{4}}]}^{2-}}\]
B) \[{{[NiC{{l}_{4}}]}^{2-}}\]
C) \[{{[ZnC{{l}_{4}}]}^{2-}}\]
D) \[{{[CoC{{l}_{4}}]}^{2-}}\]
Correct Answer: A
Solution :
\[{{\left[ PtC{{l}_{4}} \right]}^{2-}}\] has \[ds{{p}^{2}}\]hybridisation hence its geometry is square planar.
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