A) \[PtC{{l}_{2}}\]
B) P\[PtC{{l}_{4}}\]
C) \[PtC{{l}_{6}}\]
D) \[{{H}_{2}}PtC{{l}_{6}}\]
Correct Answer: D
Solution :
\[Pt+\underset{Conc.}{\mathop{2HN{{O}_{3}}}}\,+\underset{Conc.}{\mathop{6HCl}}\,\xrightarrow{{}}PtC{{l}_{4}}+2NOCl+4{{H}_{2}}O\]\[PtC{{l}_{4}}+2HCl\xrightarrow{{}}\underset{hexa\,\,chloroplatinic\,\,acid}{\mathop{{{H}_{2}}\left[ PtC{{l}_{6}} \right]}}\,\]
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