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NEET Sample Paper NEET Sample Test Paper-33

  • question_answer
    A current of 2A flowing through a conductor produces 80 J heat in 10s. The resistance of the conductor will be:

    A)  10              

    B)  20

    C)  80              

    D)  200

    Correct Answer: B

    Solution :

    According to Joule's law, rate of production of heat (H) is given by, \[H={{i}^{2}}Rt.\] Where i is current flowing in the conductor, R, the resistance and t the time.                 Here :  \[H=80J,\text{ }i=2A,\text{ }t=10s.\] \[80={{(2)}^{2}}\times R\times 10\] \[\Rightarrow \] \[R=\frac{80}{4\times 10}=2\Omega \] Note: Joule's law is associated with ohm's law. Whenever ohm's law holds. Joule's law also holds.


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