NEET Sample Paper NEET Sample Test Paper-32

  • question_answer 74) For the reaction C (graphite) \[+1/2{{O}_{2}}\,(g)\xrightarrow{{}}CO(g)\]at \[300\,K\] and 1 atm \[\Delta H=-26.4\]kcal. What is \[\Delta E\] \[(R=0.002\text{ }kcal\text{ }mo{{l}^{-1}}\text{ }{{k}^{-1}})\]

    A)  \[-26.1\text{ }kcal\]        

    B)  \[-26.7\text{ }kcal\]

    C)  \[-37.4\text{ }kcal\]         

    D)  0

    Correct Answer: B

    Solution :

    \[\Delta E=\Delta H-\Delta {{n}_{g}}RT=-26.4\,kcal-\frac{1}{2}\times \frac{2}{1000}\times 300\,kcal\]\[=-26.7\,kcal\]

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