• # question_answer 43) The temperature gradient in a rod of $0.5\text{ }m$long is${{80}^{o}}C/m$. If the temperature of hotter end of the rod is ${{30}^{o}}C,$then the temperature of the cooler end is:- A)  ${{40}^{o}}C$              B)  $-{{10}^{o}}C$C)  ${{10}^{o}}C$              D)  ${{20}^{o}}C$

Temperature gradient $=\frac{-dT}{dX}$ $\frac{{{T}_{1}}-{{T}_{2}}}{dX}=80$ $\frac{30-{{T}_{2}}}{0.5}=80$      $\Rightarrow$  ${{T}_{2}}=-{{10}^{o}}C$