NEET Sample Paper NEET Sample Test Paper-31

  • question_answer
    Balancing length for a standard cell of emf \[1.5\] volt is\[7.5\text{ }m\]. Balancing length for a \[3.5\]ohm resistance, through which a current of \[0.2\] ampere is flowing, will be :-                                                   

    A)  \[3.5\,m\]             

    B)   \[5.0\,\,m\]

    C)  \[5.7\text{ }m\]             

    D)  \[6.5\text{ }m\]

    Correct Answer: A

    Solution :

    \[x=\frac{E}{L}=\frac{1.5}{7.5}=\frac{1}{5}\] \[V=IR=x\ell '\] \[\ell '=\frac{IR}{x}=\frac{0.2\times 3.5}{\frac{1}{5}}=3.5\,m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner