A) 2
B) \[6.25\times {{10}^{18}}\]
C) \[31.25\times {{10}^{17}}\]
D) \[3.125\times {{10}^{17}}\]
Correct Answer: C
Solution :
\[I=\frac{P}{V}=\frac{110}{220}=\frac{1}{2}A\] \[I=\frac{Ne}{t}\] or \[\frac{N}{t}=\frac{I}{e}=\frac{1}{2\times 1.6\times {{10}^{-19}}}=3.125\times {{10}^{18}}\]
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