A) \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{a}}}\]
B) \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{b}}}\]
C) \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{a}}\times {{K}_{b}}}\]
D) \[{{K}_{w}}=\frac{{{K}_{h}}}{{{K}_{b}}}\]
Correct Answer: B
Solution :
\[MgC{{l}_{2}}\] is a salt of weak base and strong acid, Hence, \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{b}}}\]
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