A) 1-butanol
B) Isopropyi alcohol
C) Acetaldehyde
D) 2-butanol
Correct Answer: D
Solution :
2-Butanol has a chiral carbon atom, hence it is optically active compound. \[\underset{2-\text{butanol}}{\mathop{C{{H}_{3}}C{{H}_{2}}-\underset{H}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,*-OH}}\,\]
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