A) \[NaW{{O}_{2}}\]
B) \[NaW{{O}_{3}}\]
C) \[N{{a}_{2}}W{{O}_{3}}\]
D) \[NaW{{O}_{4}}\]
Correct Answer: B
Solution :
In a unit cell W atoms at the corner \[=\frac{1}{8}\times 8=1\] O atoms at the centre of edges \[=\frac{1}{4}\times 12=3\] Na atoms at the centre of the cube = 1 \[W:O:Na=1:3:1\] Hence the formula of the compound is \[NaW{{O}_{3}}\]
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