A) \[AgN{{O}_{3}}+NaBr\xrightarrow{{}}AgBr+NaN{{O}_{3}}\]
B) \[AgBr+2N{{a}_{2}}{{S}_{2}}{{O}_{3}}\xrightarrow{{}}N{{a}_{3}}\left[ Ag\,{{\left( {{S}_{2}}{{O}_{3}} \right)}_{2}} \right]+NaBr\]
C) \[AgBr+hv\xrightarrow{{}}AgBr*\]
D) \[{{C}_{6}}{{H}_{4}}{{(OH)}_{2}}+2AgBr*\xrightarrow{{}}{{C}_{6}}{{H}_{4}}{{O}_{2}}+2HBr+2Ag\]
Correct Answer: D
Solution :
The developoer quinol reduces exposed \[AgBr\] to black \[Ag\]. \[{{C}_{6}}{{H}_{4}}(OH)+2AgBr*\xrightarrow{{}}{{C}_{6}}{{H}_{4}}{{O}_{2}}+2HBr+2Ag\]
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