A) \[CC{{l}_{3}}N{{O}_{2}}\]
B) \[C{{H}_{3}}N{{O}_{2}}\]
C) \[C{{H}_{3}}CN\]
D) \[C{{H}_{2}}C{{H}_{2}}N{{O}_{2}}\]
Correct Answer: A
Solution :
Chloroform reacts with cone. \[HN{{O}_{3}}\] to given chloropicrin which is used as tear gas. \[CHC{{l}_{3}}+HN{{O}_{3}}\xrightarrow{\Delta }\underset{Chloropicrin}{\mathop{CC{{l}_{3}}N{{O}_{2}}}}\,+{{H}_{2}}O\]
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