A) \[Mn{{O}_{2}},\,FeC{{l}_{3}}\]
B) \[{{[Mn{{O}_{4}}]}^{-}},\,Cr{{O}_{2}}C{{l}_{2}}\]
C) \[{{[Fe{{(CN)}_{6}}]}^{3-}},[Co{{(CN)}_{3}}]\]
D) \[{{[NiC{{l}_{4}}]}^{2-}},{{[CoC{{l}_{4}}]}^{-}}\]
Correct Answer: B
Solution :
In \[MnO,\]and \[FeC{{L}_{3}}\] oxidation states of \[Mn\] and \[Fe\]are \[+4\] and \[+3\] respectively. In \[{{[Mn{{O}_{4}}]}^{-}}\]and \[Cr{{O}_{2}}C{{l}_{2}}\]oxidation state of \[Mn\] and \[Cr\] are \[+7\] and \[+6\]respectively. In \[{{[Fe{{(CN)}_{6}}]}^{3-}}\] and \[[CO{{(CN)}_{3}}]\] oxidation states of Fe and \[Co\] are \[+3\] and \[+3\] respectively. In \[{{[NiC{{l}_{4}}]}^{2-}}\] and \[{{[CoC{{l}_{4}}]}^{-}}\] oxidation states of \[Ni\] and \[Co\] are \[+2\]and \[+3\] respectively. Hence, the pair of compounds \[{{[Mn{{O}_{4}}]}^{-}}\]and \[Cr{{O}_{2}}C{{l}_{2}}\]having metals in their highest oxidation state.
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