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NEET Sample Paper NEET Sample Test Paper-2

  • question_answer
    When two tuning forks A and B sounded together produce 4 beats per second. After felling of A and waxing of B, the number of beats remain unaltered. If initial frequency of A is 250 Hz, then the initial frequency of B is:

    A)  \[246\text{ }Hz\]          

    B)  \[250\text{ }Hz\]

    C)  \[254\text{ }Hz\]            

    D)  \[242\text{ }Hz\]

    Correct Answer: C

    Solution :

    By the question, \[|250-{{V}_{B}}|=4\] \[{{V}_{B}}\] can be \[254\text{ }Hz\] or \[246\text{ }Hz\] Now on filling of A, \[{{V}_{A}}\] will increase and on waxing of B, \[{{V}_{B}}\] will decrease, For same number of beats initially, \[{{V}_{B}}>{{V}_{A}}\] \[{{V}_{B}}=254\,Hz\]


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