question_answer

\[{{H}_{2}}S\] gas when passed through a solution of cations containing \[HCl\] precipitates the cations of second group of qualitative analysis but not those belonging to the fourth group. It is because -

A)  Presence of \[HCl\] decreases the sulphide ion concentration.

B)  Sulphides of group IV cations are unstable in \[HCl\]

C)  Solubility product of group II sulphides is more than that of group IV sulphides

D)  Presence of \[HCl\] increases the sulphide ion concentration