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NEET Sample Paper NEET Sample Test Paper-28

  • question_answer
    A thin bar magnet oscillates in the horizontal plane with a time period of\[2\text{ }sec\]. If bar magnet is broken into 4 equal parts perpendicular to its length than the time period of each part will be :-

    A)  \[0.5\text{ }sec\]          

    B)  \[1.0\text{ }sec\]

    C)  \[1.5\text{ }sec\]                    

    D)  \[2.0\text{ }sec\]

    Correct Answer: A

    Solution :

    n equal parts perpendicular to the length \[T'=\frac{T}{n}\]


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