A) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}CH=CHC{{H}_{3}}\]
C) \[{{C}_{2}}{{H}_{5}}-CH=CH-C{{H}_{3}}\]
D) \[{{C}_{2}}{{H}_{5}}-CH=C{{H}_{2}}\]
Correct Answer: B
Solution :
Symmetrical alkene i.e. \[C{{H}_{3}}CH=CHC{{H}_{3}}\] gives the same product obeying Markovnikov's rule and peroxide effect.
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