A) \[J{{S}^{-1}}M{{K}^{-1}}\]
B) \[J{{S}^{-1}}{{K}^{-1}}\]
C) \[JS{{M}^{-1}}K\]
D) \[J{{S}^{-1}}{{M}^{-1}}{{K}^{-1}}\]
Correct Answer: D
Solution :
From relation, \[\frac{\Delta \theta }{\Delta t}=KA\,\frac{\Delta T}{\Delta x}\] \[\Rightarrow \] \[K=\frac{\Delta \theta }{\Delta t}\,\,.\,\,\frac{\Delta K}{A.\,\Delta T}\] \[=\frac{Jm}{S{{m}^{2}}K}=J{{S}^{-1}}{{M}^{-1}}{{K}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
