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NEET Sample Paper NEET Sample Test Paper-26

  • question_answer
    A driver applies the break on seeing traffic signal 400m ahead. At the time of applying the brakes, vehicle was moving with \[15m{{s}^{-1}}\] and retarding with \[0.3m{{s}^{-2}}\]. The distance of vehicle after 1 min from the traffic light is:

    A)  \[25\,m\]             

    B)  \[375\,m\]

    C)  \[360\,m\]                   

    D)  \[40\,m\]

    Correct Answer: A

    Solution :

    The maximum distance covered by the vehicle before coming to rest \[=\frac{{{V}^{2}}}{2a}=\frac{{{(15)}^{2}}}{2(0.3)}=375m.\] The corresponding time             \[t=\frac{V}{a}=\frac{15}{0.3}=50s\] Therefore after \[50s,\]the distance covered by the vehicle \[=375m\] from the instant of begining of braking. The distance of vehicle from the traffic after one minute \[=(400-375)\,m=25m\]


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